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#1
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Cylinder, Track, Sector, & ' Zero'.
Win98SE\DualBoot/XP 80G h/d, 512Ram nVidia MX/400 DDR Hi, Below is an excerpt from a page on H/D's; can anyone explain the Zero factor to me? Like, where is it and what does it look like when relating to the below situation. Is it a Binary Zero? (I do understand Cylinders, Tracks, & Sectors & how to multiply to get gig size.) OT question. Does anyone know what the 'AT' stands for in AT-A or SATA. (the last 'A' means ' Attachment'. ATAPI means 'AT-Attachment Program Interface, but what about the first 'AT'? Gekko ----------------------------------- |Cylinder 10-bit 1024 |Head 8-bit 256 |Sector 6-bit 63* "You will note that the number of sectors is 63 instead of 64. This is because a sector cannot begin with zero. Each sector holds 512 bytes. If you multiply 1,024 x 256 x 63 x 512, you will get 8,455,716,864 bytes or approximately 8.4 gigabytes." ----------------------------------- |
#2
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Cylinder, Track, Sector, & ' Zero'.
It's a slightly twisted way of saying that there are 63 sectors numbered
from 1 to 63 (as distinct from 1024 cylinder numbered from 0 to 1023 and 256 heads numbered from 0 to 255). There is no sector numbered zero. -- Jeff Richards MS MVP (Windows - Shell/User) "Gekko" wrote in message ... Win98SE\DualBoot/XP 80G h/d, 512Ram nVidia MX/400 DDR Hi, Below is an excerpt from a page on H/D's; can anyone explain the Zero factor to me? Like, where is it and what does it look like when relating to the below situation. Is it a Binary Zero? (I do understand Cylinders, Tracks, & Sectors & how to multiply to get gig size.) OT question. Does anyone know what the 'AT' stands for in AT-A or SATA. (the last 'A' means ' Attachment'. ATAPI means 'AT-Attachment Program Interface, but what about the first 'AT'? Gekko ----------------------------------- |Cylinder 10-bit 1024 |Head 8-bit 256 |Sector 6-bit 63* "You will note that the number of sectors is 63 instead of 64. This is because a sector cannot begin with zero. Each sector holds 512 bytes. If you multiply 1,024 x 256 x 63 x 512, you will get 8,455,716,864 bytes or approximately 8.4 gigabytes." ----------------------------------- |
#3
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Cylinder, Track, Sector, & ' Zero'.
OT question:
Advanced Technology Attachment http://en.wikipedia.org/wiki/Parallel_ATA -- Glen Ventura, MS MVP Shell/User, A+ http://dts-l.org/goodpost.htm "Gekko" wrote in message ... Win98SE\DualBoot/XP 80G h/d, 512Ram nVidia MX/400 DDR Hi, Below is an excerpt from a page on H/D's; can anyone explain the Zero factor to me? Like, where is it and what does it look like when relating to the below situation. Is it a Binary Zero? (I do understand Cylinders, Tracks, & Sectors & how to multiply to get gig size.) OT question. Does anyone know what the 'AT' stands for in AT-A or SATA. (the last 'A' means ' Attachment'. ATAPI means 'AT-Attachment Program Interface, but what about the first 'AT'? Gekko ----------------------------------- |Cylinder 10-bit 1024 |Head 8-bit 256 |Sector 6-bit 63* "You will note that the number of sectors is 63 instead of 64. This is because a sector cannot begin with zero. Each sector holds 512 bytes. If you multiply 1,024 x 256 x 63 x 512, you will get 8,455,716,864 bytes or approximately 8.4 gigabytes." ----------------------------------- |
#4
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Cylinder, Track, Sector, & ' Zero'.
Thanks Jeff & Glee.
Gekko "glee" wrote in message ... OT question: Advanced Technology Attachment http://en.wikipedia.org/wiki/Parallel_ATA -- Glen Ventura, MS MVP Shell/User, A+ http://dts-l.org/goodpost.htm "Gekko" wrote in message ... Win98SE\DualBoot/XP 80G h/d, 512Ram nVidia MX/400 DDR Hi, Below is an excerpt from a page on H/D's; can anyone explain the Zero factor to me? Like, where is it and what does it look like when relating to the below situation. Is it a Binary Zero? (I do understand Cylinders, Tracks, & Sectors & how to multiply to get gig size.) OT question. Does anyone know what the 'AT' stands for in AT-A or SATA. (the last 'A' means ' Attachment'. ATAPI means 'AT-Attachment Program Interface, but what about the first 'AT'? Gekko ----------------------------------- |Cylinder 10-bit 1024 |Head 8-bit 256 |Sector 6-bit 63* "You will note that the number of sectors is 63 instead of 64. This is because a sector cannot begin with zero. Each sector holds 512 bytes. If you multiply 1,024 x 256 x 63 x 512, you will get 8,455,716,864 bytes or approximately 8.4 gigabytes." ----------------------------------- |
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